Asked by Michael omoloye
Solve: 2x+3y=2 and x+y=5xy
Answers
Answered by
mathhelper
I believe oobleck set this up for you in an earlier post, I just can't find it.
anyhow.....
from the second,
y - 5xy = -x
y(1 - 5x) = -x
y = -x/(1-5x) = x/(5x-1) , sub that into the other
2x + 3(x/(5x-1) ) = 2
times 5x-1
10x^2 - 2x + 3x = 10x - 2
10x^2 - 9x + 2 = 0
Solve using your favorite method, hint: it factors
anyhow.....
from the second,
y - 5xy = -x
y(1 - 5x) = -x
y = -x/(1-5x) = x/(5x-1) , sub that into the other
2x + 3(x/(5x-1) ) = 2
times 5x-1
10x^2 - 2x + 3x = 10x - 2
10x^2 - 9x + 2 = 0
Solve using your favorite method, hint: it factors
Answered by
Michael omoloye
Continue from where he stop. You get -4x and -5x for the factor. Complete it.
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