Asked by p00pjoke
Solve the system by elimination.
2a + 2b - c = 2
3a 4b + 4 = -4
5a + -2b - 3c = 5
The solution is ( , , ,)
2a + 2b - c = 2
3a 4b + 4 = -4
5a + -2b - 3c = 5
The solution is ( , , ,)
Answers
Answered by
mathhelper
2nd equation makes no sense,
but I would go after the b's
but I would go after the b's
Answered by
oobleck
your post has typos. I'll guess on fixing it
#1: c = 2a+2b-2
Use that to get
3a+3b+4(2a+2b-2) = -4
5a-2b-3(2a+2b-2) = 5
or,
11a+11b = 4
11a+11b = 4
so there is no unique solution.
Maybe you can fix your typos and work it out as I tried to.
#1: c = 2a+2b-2
Use that to get
3a+3b+4(2a+2b-2) = -4
5a-2b-3(2a+2b-2) = 5
or,
11a+11b = 4
11a+11b = 4
so there is no unique solution.
Maybe you can fix your typos and work it out as I tried to.
Answered by
p00pjoke
Sorry oobleck, it was supposed to say 3a + 4b + c = 5
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.