2nd equation makes no sense,
but I would go after the b's
Solve the system by elimination.
2a + 2b - c = 2
3a 4b + 4 = -4
5a + -2b - 3c = 5
The solution is ( , , ,)
3 answers
your post has typos. I'll guess on fixing it
#1: c = 2a+2b-2
Use that to get
3a+3b+4(2a+2b-2) = -4
5a-2b-3(2a+2b-2) = 5
or,
11a+11b = 4
11a+11b = 4
so there is no unique solution.
Maybe you can fix your typos and work it out as I tried to.
#1: c = 2a+2b-2
Use that to get
3a+3b+4(2a+2b-2) = -4
5a-2b-3(2a+2b-2) = 5
or,
11a+11b = 4
11a+11b = 4
so there is no unique solution.
Maybe you can fix your typos and work it out as I tried to.
Sorry oobleck, it was supposed to say 3a + 4b + c = 5