Asked by Alisha
A sled of 6 kg mass is moving along a smooth, horizontal ice surface with a velocity of Vo. A force of 36 N is applied to the sled in it direction of motion, increasing its velocity to 2Vo when it moves 10 m. find the sleds original velocity, Vo and the length of time the force acted.
Answers
Answered by
Anonymous
36 = 6 a
a = 6 = change in velocity / time = Vo/t
d = 10 meters = average speed * t = 1.5 Vo t
so Vo = 10 / 1.5 t
so
6 = ( 10 /1.5 t) / t
6 t = 10/1.5t
9 t^2 = 10
t = 1.05 seconds
Vo = 10/1.5 t = 6.35m/s
=======================
check
Vo = 6.35
2 Vo = 12.7
1.5 Vo = 9.52
t = 10 m / 9.52 m/s = 1.05 s
a = dv/dt = 6.35 / 1.05 = 6.05 m/s^2
F = m a = 6 *6.05 = 36.3 Newtons, close enough
a = 6 = change in velocity / time = Vo/t
d = 10 meters = average speed * t = 1.5 Vo t
so Vo = 10 / 1.5 t
so
6 = ( 10 /1.5 t) / t
6 t = 10/1.5t
9 t^2 = 10
t = 1.05 seconds
Vo = 10/1.5 t = 6.35m/s
=======================
check
Vo = 6.35
2 Vo = 12.7
1.5 Vo = 9.52
t = 10 m / 9.52 m/s = 1.05 s
a = dv/dt = 6.35 / 1.05 = 6.05 m/s^2
F = m a = 6 *6.05 = 36.3 Newtons, close enough
Answered by
Ukram
How’d you find time ?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.