Asked by Ann
A sled of mass 9.0 kg is sliding across a frozen lake with a speed of 5.0 m/s. A package of mass 4.0 kg is dropped onto it from above. Assuming there is no friction between the sled and the lake, what is the new speed of the sled?
Answers
Answered by
YA
By the law of conservation of momentum,
m1v1 = m2v2
9 * 5 = (9+4) v2
v2 = 45/13
m1v1 = m2v2
9 * 5 = (9+4) v2
v2 = 45/13
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