Question
A sled of mass 9.0 kg is sliding across a frozen lake with a speed of 5.0 m/s. A package of mass 4.0 kg is dropped onto it from above. Assuming there is no friction between the sled and the lake, what is the new speed of the sled?
Answers
By the law of conservation of momentum,
m1v1 = m2v2
9 * 5 = (9+4) v2
v2 = 45/13
m1v1 = m2v2
9 * 5 = (9+4) v2
v2 = 45/13
Related Questions
A wind sled has a mass of 45kg and is gliding at a speed of 2m/s over the frozen lake with neglible...
A man holding a rock sits on a sled that is sliding across a frozen lake (negligible friction) with...
A child on a sled is sliding at a speed of 4m/s across level ice. if the total mass of the sled + ch...