Asked by Anonymous
A sled of mass m = 70.0 kg is being pulled horizontally on a frictionless floor by a force F = 420 N that makes an angle 20.0o above the horizontal. What is the magnitude of the normal force applied by the ground on the sled?
Answers
Answered by
Henry
M*g = 70 * 9.8 = 686 N. = Wt. of sled.
Fn = Mg-F*sin20 =
Fn = Mg-F*sin20 =
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