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An extreme skier takes off from a jump and is going for height? if she leaves the jump traveling 13 m/s as she reaches the top of her flight, how high does she get above the top of the ramp?
3 years ago

Answers

oobleck
depends on the angle of the ramp at takeoff.
H = v^2/(2g) sin^2θ
all we know so far is that v cosθ = 13
3 years ago

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