Asked by Anonymous
An extreme skier takes off from a jump and is going for height? if she leaves the jump traveling 13 m/s as she reaches the top of her flight, how high does she get above the top of the ramp?
Answers
Answered by
oobleck
depends on the angle of the ramp at takeoff.
H = v^2/(2g) sin^2θ
all we know so far is that v cosθ = 13
H = v^2/(2g) sin^2θ
all we know so far is that v cosθ = 13
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.