Asked by Anonymous

An extreme skier takes off from a jump and is going for height? if she leaves the jump traveling 13 m/s as she reaches the top of her flight, how high does she get above the top of the ramp?

Answers

Answered by oobleck
depends on the angle of the ramp at takeoff.
H = v^2/(2g) sin^2θ
all we know so far is that v cosθ = 13
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