Asked by Adeleke
                Two numbers differ by 6,the difference of their squares is 120.find the numbers 
            
            
        Answers
                    Answered by
            Adeleke
            
    Help me solve this pls
    
                    Answered by
            PsyDAG
            
    x = y - 6
x^2 - y^2 = (y-6)^2 - y^2 = 120
Solve for y, then x.
    
x^2 - y^2 = (y-6)^2 - y^2 = 120
Solve for y, then x.
                    Answered by
            Rafiu Diekolola
            
    Let the numbers be x and y
x-y=6,x^2-y^2=120
the solve for x and y
    
x-y=6,x^2-y^2=120
the solve for x and y
                    Answered by
            Anonymous
            
    Two numbers differ by 6 ,the difference of their square is 120.Find the number
    
                    Answered by
            Joshua
            
    Two numbers differ by 6 ,the difference of their square is 120.Find the number
    
                    Answered by
            Joshua
            
    Two numbers differ by 6 ,the difference of their square is 120.Find the number
    
                    Answered by
            Esther
            
    y-x=6,y^2-x^2=120.
x=y-6
y^2-(y-6)^2=120
y^2-y^2+6^2=120
y^2-
    
x=y-6
y^2-(y-6)^2=120
y^2-y^2+6^2=120
y^2-
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