Asked by TUHITUHI
two numbers differ by 11 and 1/3rd of the greater exceeds 1/4th of the other by 7 . find the number ???
Answers
Answered by
Anonymous
let the no. be x and y...
x - y = 7.........i
1/3 x- 1/4 y =7..........ii
eq ii x 12
4x - 3y = 84.....iii
subtracting i and iii
y=40
substituting in any eq x=51
x - y = 7.........i
1/3 x- 1/4 y =7..........ii
eq ii x 12
4x - 3y = 84.....iii
subtracting i and iii
y=40
substituting in any eq x=51
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