I have idea what you're doing? What's the procedure. What's the starting material? You need to explain what's going on.
IF the sample is 100% ferrous ammonium sulfate hydrate then you will have 1.0714 of that material, of course.
Calculate the mass of Fe(NH4)2(SO4)26H2O in your unknown sample. Show you work.
Average mass of unknown sample:1.0714g
PLEASE EXPLAIN CALCULATION PROCESS
3 answers
IRON ANALYSIS BY REDOX TITRATION
Percent Fe in unknown sample is 70.5%.
Theoretical % Fe in Fe(NH4)2(SO4)26H2O is 14.24%
THE SAMPLE IS UNKOWN
@DrBob222
Percent Fe in unknown sample is 70.5%.
Theoretical % Fe in Fe(NH4)2(SO4)26H2O is 14.24%
THE SAMPLE IS UNKOWN
@DrBob222
Please check you numbers and repost everything. The value I'm getting for the grams of ferrous ammonium sulfate hexahydrate in a 1.0714 g sample and 70.5% Fe just doesn't seem possible.
3 answers