Asked by Tiauna
Suppose that 16.07 mL of 0.0512 M NaOH were required to titrate a sample of unknown acid. How many moles of NaOH were used? Assuming that the unknown acid sample in question 1 had a mass of 0.177 g, what is the molar mass of the unknown acid?
Answers
Answered by
DrBob222
Is this a monoprotic acid or otherwise?
I assume monoprotic.
mols NaOH = M x L = ?
mols acid = mols NaOH (if acid is monoprotic)
mols acid = grams/molar mass.
You know grams of the acid and mols of the acid, solve for molar mass.
I assume monoprotic.
mols NaOH = M x L = ?
mols acid = mols NaOH (if acid is monoprotic)
mols acid = grams/molar mass.
You know grams of the acid and mols of the acid, solve for molar mass.
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