Asked by Anonymous
                What is the maximum value of the function?
h(t) = -8t^2 + 9t - 7
I got -1144/256 as my maximum value
That just doesn't look right to me though. I don't know...
            
        h(t) = -8t^2 + 9t - 7
I got -1144/256 as my maximum value
That just doesn't look right to me though. I don't know...
Answers
                    Answered by
            oobleck
            
    reduced, that is -143/32
the max/min value at x = -b/2a is (4ac-b^2)/4a = (4*8*7 - 81)/-32 = -143/32
    
the max/min value at x = -b/2a is (4ac-b^2)/4a = (4*8*7 - 81)/-32 = -143/32
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