Asked by maria
The height of a ball thrown from the top of a building can be modeled by the equation, where h is the height in feet and t is time in seconds.
h(t)=−16t^2+55t+214
I already got the height of the building correct....=214 feet
I got the maximumheight of ball =1.7188 secs
i got height of the ball= 261.2656 feet.
BUT I need help with D)
(d) The time it takes for the ball to reach the ground:
thank you kindly
h(t)=−16t^2+55t+214
I already got the height of the building correct....=214 feet
I got the maximumheight of ball =1.7188 secs
i got height of the ball= 261.2656 feet.
BUT I need help with D)
(d) The time it takes for the ball to reach the ground:
thank you kindly
Answers
Answered by
oobleck
just solve h(t) = 0
t = 5.76
t = 5.76
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