The height, s, of a ball thrown straight down with initial speed 32 ft/sec from a cliff 48 feet high is s(t) = -16t^2 - 32t + 48, where t is the time elapsed that the ball is in the air. What is the instantaneous velocity of the ball when it hits the ground?

Answer 1

well, what is t when s=0?

Use that value to calculate v(t) = -32t-32

Answer 2

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