Asked by Potatoes
The height of a ball thrown upward on the moon with a velocity of 8 meters per second can be modeled by h=-0.8t^2+8t, where h is the height of the ball in meters and t is the time in seconds. At what times will the height of the ball reach 19.2 meters
Answers
Answered by
oobleck
just solve
-0.8t^2+8t = 19.2
using the quadratic formula
Or, to make things a bit simpler,
8t^2 - 80t + 192 = 0
t^2 - 10t + 24 = 0
which you can easily factor
-0.8t^2+8t = 19.2
using the quadratic formula
Or, to make things a bit simpler,
8t^2 - 80t + 192 = 0
t^2 - 10t + 24 = 0
which you can easily factor
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