Asked by christian
Find the perimeter of the polygon with the vertices Q(-3,2), R(1,2), S(1,-2) and T(-3,-2)
Answers
Answered by
Anonymous
d1 = sqrt [ (2-2)^2 + (1+3)^2 ]
d2 = sqrt [ (-2-2)^2 + (1-1)^2 ]
d3 = sqrt [ (-2+2)*2 +(-3-1)^2 ]
d4 = sqrt[ (2+2)^2 + (-3+3)^2 ]
add the four lengths
d2 = sqrt [ (-2-2)^2 + (1-1)^2 ]
d3 = sqrt [ (-2+2)*2 +(-3-1)^2 ]
d4 = sqrt[ (2+2)^2 + (-3+3)^2 ]
add the four lengths
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