Question
find the perimeter of the polygon with vertices A(-5,-3) B(1,0) C (3,-4) D(-3,-7)
Answers
MathMate
The distance between two given points P1(x1,y1) and P2(x2,y2) in the coordinate plane is given by the expression:
distance P1-P2 = sqrt((x2-x1)^2+(y2-y1)^2)
A(-5,-3) B(1,0) C (3,-4) D(-3,-7)
For example, the distance
AB = sqrt((1-(-5))^2+(0-(-3))^2)
= sqrt(6^2+3^2)
= sqrt(45)
= 6.708...(approx.)
Proceed the same way for BC, CD and CA and add up the four distances to get the perimeter.
distance P1-P2 = sqrt((x2-x1)^2+(y2-y1)^2)
A(-5,-3) B(1,0) C (3,-4) D(-3,-7)
For example, the distance
AB = sqrt((1-(-5))^2+(0-(-3))^2)
= sqrt(6^2+3^2)
= sqrt(45)
= 6.708...(approx.)
Proceed the same way for BC, CD and CA and add up the four distances to get the perimeter.