Question

Find the perimeter of the polygon using the distance formula of Triangle ABC with vertices A(3, 5), B(3, 1), C(0, 1)

Answer 1

AB = sqrt((3-3)² + (1-5)²) = sqrt(9+16) = 5
BC = sqrt((0-3)² + (1-1)²) = sqrt(9+0) = 3
CA = sqrt((0-3)² + (1-5)²) = sqrt(9+16) = 5

Take it from here.