Asked by fsgdfgsd
Find the perimeter of the polygon using the distance formula of Triangle ABC with vertices A(3, 5), B(3, 1), C(0, 1)
Answers
Answered by
Steve
AB = sqrt((3-3)² + (1-5)²) = sqrt(9+16) = 5
BC = sqrt((0-3)² + (1-1)²) = sqrt(9+0) = 3
CA = sqrt((0-3)² + (1-5)²) = sqrt(9+16) = 5
Take it from here.
BC = sqrt((0-3)² + (1-1)²) = sqrt(9+0) = 3
CA = sqrt((0-3)² + (1-5)²) = sqrt(9+16) = 5
Take it from here.
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