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a mixture of gases contains 64g of methane, 64g of oxygen and 64g of sulphur dioxide. The pressure of the mixture is 210 kpa. w...Asked by yasir
A mixture of gases contains 64g of methane, 64g of oxygen and 64g of sulphur dioxide.
The pressure of the mixture is 2l0kPa. What is the partial pressure (in kPa) of the methane
expected to be?
The pressure of the mixture is 2l0kPa. What is the partial pressure (in kPa) of the methane
expected to be?
Answers
Answered by
DrBob222
mols CH4 = g/molar mass = 64/16 = 4
mols O2 = 64/32 = 2
mols SO3 = 64/80 = 0.8
Total mol = 6.8
mol fraction CH4 = X<sub>CH4</sub> = 4/6.8 = 0.588 round to 0.59
pCH4 = XCH4*Ptotal
pCH4 = 0.59*210 = ? in kPa.
mols O2 = 64/32 = 2
mols SO3 = 64/80 = 0.8
Total mol = 6.8
mol fraction CH4 = X<sub>CH4</sub> = 4/6.8 = 0.588 round to 0.59
pCH4 = XCH4*Ptotal
pCH4 = 0.59*210 = ? in kPa.
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