Question

A mixture of gases contains 0.235 mol CO2, 0.124 mol CO, and 0.326 mol O2. If the total
pressure of the mixture is 4.62 atm, what is the partial pressure of each gas?

Answer 1

XCO2 = mols CO2/total mols.
XCO = mols CO/total mols
XO2 = mols O2/total mols.

pCO2 = XCO2*Ptotal
pCO = XCO*Ptotal
pO2 = XO2*Ptotal

Answer 2

co2=1.58
co-0.836
o2-2.24