Question
A mixture of gases contains 2.00 mol of O2, 3.00 mol of N2, and 5.00 mol of He. The total pressure of the mixture is 850 torr. What is the partial pressure of each gas?
Answers
Damon
PV = nRT
V, R and T are constant
in other words the pressure of each is proportional to n
total moles = 2+3+5 = 10 mol
P of O2 = 850 (2/10)
P of N2 = 850 (3/10) etc
V, R and T are constant
in other words the pressure of each is proportional to n
total moles = 2+3+5 = 10 mol
P of O2 = 850 (2/10)
P of N2 = 850 (3/10) etc
Anonymous
Wedc