Question

A ball is thrown straight down from the top of a 500-foot building with an initial velocity of -19 feet per second. Use the position function below for free-falling objects.

s(t) = -16t2 + v0t + s0

What is its velocity after 3 seconds?
V(2)= _____ ft/s

What is its velocity after falling 332 feet?
V= _____ ft/s
really? they gave you the equation and the values to use, so ...
s(t) = -16t^2 - 19t + 500
v(t) = ds/dt = -32t - 19

(a) plug in t=3
(b) find t when s = 500-332 = 168
then use that to find v(t)

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