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Asked by Amit

prove that
(3-4sin^2x)(sec^2x-tan^2x) = (3-tan^2x)(1-4sin^2x)
4 years ago

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Answered by oobleck
as written, this is false.
when x = π/4, you have
1 = -2
4 years ago
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prove that
(3-4sin^2x)(sec^2x-tan^2x) = (3-tan^2x)(1-4sin^2x)

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