Asked by JAYZ
Given f''(x)= -4sin(2x) and f'(0)=4 and f(0) =-6. Find f(pi/2)
Answers
Answered by
Steve
f" = -4sin2x
f' = 2cos2x + c
2+c = 4
c=2
so, f' = 2cos2x + 2
f = sin2x + 2x + c
0+0+c = -6
c = -6
so, f = sin2x + 2x - 6
f' = 2cos2x + c
2+c = 4
c=2
so, f' = 2cos2x + 2
f = sin2x + 2x + c
0+0+c = -6
c = -6
so, f = sin2x + 2x - 6
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