Asked by Natalia
                Resuelve los sistemas de ecuaciones lineales que se proponen. Exhibe, de ser posible, dos soluciones particulares.
2x-y+3z=-1,
2x+4y-2z=5
            
        2x-y+3z=-1,
2x+4y-2z=5
Answers
                    Answered by
            oobleck
            
    y = 13/10 - x
z = 1/10 - x
so an easy solution would be
x = 1
y = 3/10
z = -9/10
pick any other values you like for x. Can you think of any where all are integers?
    
z = 1/10 - x
so an easy solution would be
x = 1
y = 3/10
z = -9/10
pick any other values you like for x. Can you think of any where all are integers?
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