Asked by andy
A gas pipe line is to be constructed from a storage tank, which is right on a road, to a house which is
600 feet down the road from the tank and 300 feet set back from the road. Pipe laid along the road cost
$8.00/ft while the pipe laid off the road costs $10.00/ft. What is the minimum cost for which this pope
line can be built? Make an objective function with two variables and state the constraints
600 feet down the road from the tank and 300 feet set back from the road. Pipe laid along the road cost
$8.00/ft while the pipe laid off the road costs $10.00/ft. What is the minimum cost for which this pope
line can be built? Make an objective function with two variables and state the constraints
Answers
Answered by
oobleck
So, draw the diagram. If the pipeline is in straight segments, and leaves the road x feet from the tank, then the overland distance is
√((600-x)^2 + 300^2)
so the cost of the pipeline is
c(x) = 8x + 10√((600-x)^2 + 300^2)
dc/dx = 8 - 10(600-x)/√((600-x)^2 + 300^2)
dc/dx=0 at x=200, so the minimum cost is c(200) = $6600
√((600-x)^2 + 300^2)
so the cost of the pipeline is
c(x) = 8x + 10√((600-x)^2 + 300^2)
dc/dx = 8 - 10(600-x)/√((600-x)^2 + 300^2)
dc/dx=0 at x=200, so the minimum cost is c(200) = $6600
Answered by
help
how did you get x =200??
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