Asked by Anonymous
A horse breeder wants to construct a corral next to a horse barn that is L=20 feet long, using the barn as part of one side of the corral as shown in the figure above. The breeder has 320 feet of fencing available.
Answers
Answered by
Steve
If the corral has dimensions x and y, with the barn as a part of side y, then
2x+2y-20 = 320
There are lots of values for x and y that fit that requirement. If y is the long side, then we just need x+y=150, so any value of y between 75 and 150 will work fine, but some of the corrals will be long and thin!
I expect the unseen figure puts further constraints on x and y.
2x+2y-20 = 320
There are lots of values for x and y that fit that requirement. If y is the long side, then we just need x+y=150, so any value of y between 75 and 150 will work fine, but some of the corrals will be long and thin!
I expect the unseen figure puts further constraints on x and y.
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