Asked by John
A projectile fired with an know initial velocity lands 20s later on the side of a hill 3000m away horizontally and 450m vertically above its strating point . Find the horizontal and vertical components of its initial velocity
Answers
Answered by
R_scott
horizontal velocity is constant ... v = 3000 m / 20 s
vertical velocity is subject to gravitational acceleration
... 450 m = [-1/2 * g * (20 s)^2] + (v * 20 s)
vertical velocity is subject to gravitational acceleration
... 450 m = [-1/2 * g * (20 s)^2] + (v * 20 s)
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