Asked by Butterfly girl
                The volume V of a pyramid varies jointly as the area of it’s base B and its height h. If the volume of the pyramid is 24 cubic meters when the area of it’s base is 18 square meters and its height is 4 meters find the volume of a pyramid when the area of it’s base is 21 square meters and its height is 7 meters.
            
            
        Answers
                    Answered by
            Anonymous
            
    v = k B h
24 = k* 18 * 4
k = 24 / 72 = 1/3 If you did not already know volume of pointy object with straight sides = (1/3) * base area * height
so
V = (1/3) * 21 * 7 = 7 * 7 = 49
    
24 = k* 18 * 4
k = 24 / 72 = 1/3 If you did not already know volume of pointy object with straight sides = (1/3) * base area * height
so
V = (1/3) * 21 * 7 = 7 * 7 = 49
                    Answered by
            mathhelper
            
    Volume = k(base)(height)
given: Vol = 24 m^3, base = 18 m^2 , height = 4 m
24 m^3 = k(18)(4) m^3
k = 24/(18*4) = 1/3
Vol = (1/3)(base)(height)
when base = 21, height = 7
Vol = (1/3)(21 m^2)(7 m) = 49 m^3
    
given: Vol = 24 m^3, base = 18 m^2 , height = 4 m
24 m^3 = k(18)(4) m^3
k = 24/(18*4) = 1/3
Vol = (1/3)(base)(height)
when base = 21, height = 7
Vol = (1/3)(21 m^2)(7 m) = 49 m^3
                    Answered by
            Miracle
            
    What a good answer. Brilliant girl.
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.