Asked by leah
The volume V of a pyramid varies jointly as its height h and the area of its base B . Given that the volume of the pyramid is 60 cubic inches when the height is 5 inches and area of its base is 36 square inches, what is the area of the base if its volume is doubled and the height is halved?
Answers
Answered by
Steve
V = kBh
B = V/kh
Now you just find B' where
B' = V'/kh' = (2V)/(k*h/2) = 4V/kh = 4B = 4*36 = 144
B = V/kh
Now you just find B' where
B' = V'/kh' = (2V)/(k*h/2) = 4V/kh = 4B = 4*36 = 144
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