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Original Question
A Mass Of 2.0kg Is Hung Off A Spring,which Extends 2cm. Determine The Energy Stored In The Spring.Asked by Gelila
A Mass of 2kg hung off a spring .which extend 2 cm determine the energy stored in the spring
Answers
oobleck
F = kx ==> k = F/x
E = 1/2 kx^2 = 1/2 * F/x * x^2 = Fx/2 = mgx/2
watch the units
E = 1/2 kx^2 = 1/2 * F/x * x^2 = Fx/2 = mgx/2
watch the units
R_scott
the energy stored in the spring is the change
... in the gravitational P.E. of the mass
E = m g h = 2 * 9.8 * .02 Joules
... in the gravitational P.E. of the mass
E = m g h = 2 * 9.8 * .02 Joules