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A mass hung from a spring stretches the spring by 11 cm when the mass is resting at its equillibrium position. What will be the frequency of oscillation of this system if the mass is put in motion?
9 years ago

Answers

bobpursley
angFreq=sqrt(k/m)

k=mass*g/.11
2PI*freq=sqrt(9.8/.11)
solve for freq in hz
9 years ago

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