Asked by Zac
A mass hung from a spring stretches the spring by 11 cm when the mass is resting at its equillibrium position. What will be the frequency of oscillation of this system if the mass is put in motion?
Answers
Answered by
bobpursley
angFreq=sqrt(k/m)
k=mass*g/.11
2PI*freq=sqrt(9.8/.11)
solve for freq in hz
k=mass*g/.11
2PI*freq=sqrt(9.8/.11)
solve for freq in hz
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.