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Original Question
What volume of 0.402MK3PO4 is required to react with 43 mL of 0.507 M MgCl2 according to the equation 2K3PO4 + 3MgCl2 ! Mg3(PO4...Asked by Hrgn
What volume of 0.704 M K3PO4 is required to
react with 48 mL of 0.975 M MgCl2 according
to the equation
2 K3PO4 + 3 MgCl2 → Mg3(PO4)2 + 6 KCl
Answer in units of mL.
react with 48 mL of 0.975 M MgCl2 according
to the equation
2 K3PO4 + 3 MgCl2 → Mg3(PO4)2 + 6 KCl
Answer in units of mL.
Answers
Answered by
DrBob222
I worked the same problem, but with different numbers, for Josh just a few questions above. Here is a link to get there. Post your work if you get stuck.
https://www.jiskha.com/questions/1865225/what-volume-of-0-649-m-k3po4-is-required-to-react-with-26-ml-of-0-453-m-mgcl2-according-to
https://www.jiskha.com/questions/1865225/what-volume-of-0-649-m-k3po4-is-required-to-react-with-26-ml-of-0-453-m-mgcl2-according-to