Question

koh + co3(po4)2 --> k3po4 + co(oh)2

Answer 1

To balance the given chemical reaction, \( \text{KOH} + \text{Co}_3(\text{PO}_4)_2 \rightarrow \text{K}_3\text{PO}_4 + \text{Co(OH)}_2 \), we'll follow these steps:

1. **Identify the chemical species involved:**
- Reactants: KOH and Co₃(PO₄)₂
- Products: K₃PO₄ and Co(OH)₂

2. **Write the unbalanced equation:**
\[
\text{KOH} + \text{Co}_3(\text{PO}_4)_2 \rightarrow \text{K}_3\text{PO}_4 + \text{Co(OH)}_2
\]

3. **Count the number of each type of atom on the reactants and products sides:**
- Reactants:
- K: 1
- O: 3 (from 1 KOH) + 8 (from 1 Co₃(PO₄)₂) = 11
- Co: 3
- P: 2
- H: 1
- Products:
- K: 3
- O: 4 (from 1 K₃PO₄) + 2 (from 1 Co(OH)₂) = 6
- Co: 1
- P: 1
- H: 2

4. **Balance the equation:**
Starting with K and P:
- To balance K, we can start with 3 KOH on the left side, which will give us 3 K on the