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How many moles of K3PO4 are required to react completely with 4.5 moles of CaCl2

2K3PO4 + 3CACl -> Ca3(PO4)2 + 6KCL

User Icon for GK GK answered
15 years ago

2K3PO4 + 3CaCl2 -> Ca3(PO4)2 + 6KCL

We use the coefficients in the chemical equation to set up:
(4.5 mol. CaCl2)(2 mol K3PO4 / 3 mol CaCl2) = ?? _____ moles K3PO4
Notice I used DOUBLE labels. Do the unit cancellation which can't be shown here.

NOTE: The above method I used is called the unit factor, factor label, or dimensional analysis method. All chemistry textbooks show it in the answered examples. I highly recommend it.

User Icon for Step-by-Step Bot Step-by-Step Bot answered
1 year ago

To find out how many moles of K3PO4 are required to react completely with 4.5 moles of CaCl2, we need to use the stoichiometry of the balanced equation. From the balanced equation:

2K3PO4 + 3CaCl2 -> Ca3(PO4)2 + 6KCl

We can see that for every 2 moles of K3PO4, 3 moles of CaCl2 are required.

Therefore, we can set up a ratio:

2 moles K3PO4 / 3 moles CaCl2 = x moles K3PO4 / 4.5 moles CaCl2

Cross-multiplying, we get:

(2 moles K3PO4) * (4.5 moles CaCl2) = (3 moles CaCl2) * (x moles K3PO4)

9 moles K3PO4 = 3 * x moles K3PO4

Simplifying the equation, we find:

9 moles K3PO4 = 3x

Dividing both sides by 3:

x = 9 moles K3PO4 / 3

x = 3 moles K3PO4

Therefore, 3 moles of K3PO4 are required to react completely with 4.5 moles of CaCl2.

User Icon for Explain Bot Explain Bot answered
1 year ago

To determine the number of moles of K3PO4 required to react completely with 4.5 moles of CaCl2, we need to use the stoichiometry of the balanced chemical equation.

According to the balanced equation:
2 moles of K3PO4 react with 3 moles of CaCl2.

We can set up a proportion to find the number of moles of K3PO4:
(2 moles K3PO4 / 3 moles CaCl2) = (x moles K3PO4 / 4.5 moles CaCl2)

Cross-multiplying the equation, we get:
2 moles K3PO4 = (3 moles CaCl2 * x moles K3PO4) / 4.5 moles CaCl2

Simplifying the equation:
2 = (3 * x) / 4.5

Now, solving for x, we can multiply both sides of the equation by 4.5 and divide by 3:
2 * 4.5 = 3 * x
9 = 3 * x
x = 9 / 3
x = 3

Therefore, 3 moles of K3PO4 are required to react completely with 4.5 moles of CaCl2.