Asked by Arielle Smith
solve for exact solutions over the interval of 0, 2pi by first solving the trigonometric function 6 sin x +12=9
Answers
Answered by
oobleck
6sinx + 12 = 9
6sinx = -3
sinx = -1/2
your reference angle is π/6
so place that angle in QII, QIV where sinx < 0
6sinx = -3
sinx = -1/2
your reference angle is π/6
so place that angle in QII, QIV where sinx < 0
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