Asked by Lily
Find the exact solutions of x^2 - (y - 6)^2 = 36 and y = -x^2.
(0,0), (6,6), and (-6,6)?
(0,0), (6,6), and (-6,6)?
Answers
Answered by
Steve
Hmmm.
y = -x^2 so
x^2 - (-x^2-6)^2 = 36
x^2 - x^4 - 12x^2 - 36 = 36
x^4 + 11x^2 + 72 = 0
I don't see any real solutions. 11^2-4*72 < 0
y = -x^2 so
x^2 - (-x^2-6)^2 = 36
x^2 - x^4 - 12x^2 - 36 = 36
x^4 + 11x^2 + 72 = 0
I don't see any real solutions. 11^2-4*72 < 0
Answered by
Lily
Thanks
Answered by
Steve
And yet, I do see that your points work.
Hmmm.
Hmmm.
Answered by
Steve
No, they don't they fit the first equation, but not the 2nd.
Only (0,0) works in both
Only (0,0) works in both
Answered by
Steve
Nope. (0,0) does not work in the 1st.
0 - 36 ≠ 36
Can't believe I let you fool me! :-)
0 - 36 ≠ 36
Can't believe I let you fool me! :-)
Answered by
Lily
At this point, I'm fooling myself!:-)
Answered by
lola
(0-6)^2=36
(-6)^2=36
36=36
(-6)^2=36
36=36
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