Asked by Roso
In a certain shipment of 14 phones, 8 are defective. 10 of the phones are selected at random without replacement. What is the probability that 5 of the 10 phones are defective?
I'm not sure how I would go about doing this?
I'm not sure how I would go about doing this?
Answers
Answered by
mathhelper
Prob(phone is defective) = 8/14 = 4/7
so prob(not defective) = 3/7
Prob(5 of 10 are defective) = C(10,5)(4/7)^5 (3/7)^5
= 252(1024/16807)(243/16807) = .....
This question falls in the category of
Binomial Distribution Probability
so prob(not defective) = 3/7
Prob(5 of 10 are defective) = C(10,5)(4/7)^5 (3/7)^5
= 252(1024/16807)(243/16807) = .....
This question falls in the category of
Binomial Distribution Probability
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.