Asked by Christian
In a shipment of 20 computer 3 are defective three computers are randomly selected and tested what is the probability that all three are defective if the first and second ones are not replaced after being tested?
Answers
Answered by
mathhelper
What is
(3/20)(2/19)(1/(18) ?
(3/20)(2/19)(1/(18) ?
Answered by
CookieCrumbs/Pro-Truth-Efficient
The answer would be 1/1140
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