Asked by e=mc^2
                Help! I need an explanation of how to do this:
(3x-1)(5x+4)
            
        (3x-1)(5x+4)
Answers
                    Answered by
            mathhelper
            
    Sometimes referred to as the FOIL pattern:
F: multiply the First times the First ---> (3x)(5x) = 15x^2
O: multiply the Outers ----> (3x)(4) = 12x
I: multiply the Inners ----> (-1)(5x) = -5x
L: multiply the Lasts ----> (-1)(+4) = -4
add them up
15x^2 + 12x - 5x - 4
= 15x^2 + 7x - 4
    
F: multiply the First times the First ---> (3x)(5x) = 15x^2
O: multiply the Outers ----> (3x)(4) = 12x
I: multiply the Inners ----> (-1)(5x) = -5x
L: multiply the Lasts ----> (-1)(+4) = -4
add them up
15x^2 + 12x - 5x - 4
= 15x^2 + 7x - 4
                    Answered by
            e=mc^2
            
    Thanks @mathhelper ! it was correct
    
                    Answered by
            e=mc^2
            
    And it really helped! Hence your username
    
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