Asked by Cheah
express y in terms of x \log _(8)y=\log _(2)x
Answers
Answered by
oobleck
since 8 = 2^3, log_8(y) = 1/3 log_2(y)
so, now we have
1/3 log_2(y) = log_2(x)
log_2( ∛y) = log_2(x)
∛y = x
y = x^3
so, now we have
1/3 log_2(y) = log_2(x)
log_2( ∛y) = log_2(x)
∛y = x
y = x^3
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