Asked by Anonymous
Express log A in terms of the
2
logarithms of prime numbers:
A= (sqrt(3)*sqrt4(125))/7^3
2
logarithms of prime numbers:
A= (sqrt(3)*sqrt4(125))/7^3
Answers
Answered by
Steve
Assuming that sqrt4(125) means ∜125, then
A = 3^(1/2) * 5^(3/4) / 7^3
so,
logA = (1/2)log3 + (3/4)log5 - 3log7
The base of the logs does not matter. The rules still hold.
A = 3^(1/2) * 5^(3/4) / 7^3
so,
logA = (1/2)log3 + (3/4)log5 - 3log7
The base of the logs does not matter. The rules still hold.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.