Asked by Nikhil
Express P(x)=2-3x+4x² in terms of legend polynomial
Answers
Answered by
Steve
Do you mean Legendre polynomials?
P<sub><sub>0</sub></sub>(x) = 1
P<sub><sub>1</sub></sub>(x) = x
P<sub><sub>2</sub></sub>(x) = 1/2 (3x^2-1)
So, x^2 = (2P<sub><sub>2</sub></sub>(x)+1)/3
4x^2-3x+2 = =4*(2P<sub><sub>2</sub></sub>(x)+1)/3 - 3P<sub><sub>1</sub></sub>(x) + 2P<sub><sub>0</sub></sub>(x)
P<sub><sub>0</sub></sub>(x) = 1
P<sub><sub>1</sub></sub>(x) = x
P<sub><sub>2</sub></sub>(x) = 1/2 (3x^2-1)
So, x^2 = (2P<sub><sub>2</sub></sub>(x)+1)/3
4x^2-3x+2 = =4*(2P<sub><sub>2</sub></sub>(x)+1)/3 - 3P<sub><sub>1</sub></sub>(x) + 2P<sub><sub>0</sub></sub>(x)
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