Question

A 0.6-kg object moves in a horizontal circular track with a radius of 3.3m. An external force of 6.8 N, always tangent to the track , causes the object to speed up as it goes around. The work done by the external force as the object makes one revolution is equal to what value in Joule?

Answer 1

force * distance in direction of the force = work done by force = 6.8 N * 2 pi * 3.3 meters = 141 Joules