Asked by Alex
A 1200kg car moves along a horizontal road at speed v0=23.3m/s,the road is wet, so the static friction coefficient between the road and the tires is only µs=0.209 and the kinetic friction coefficient is even lower µk=0.1463. The acceleration due to gravity is 9.8m/s^2. Assume: No aerodynamic forces; g=9.8m/s^2, forward is the positive direction. What is the highest possible deceleration of the car under such conditions? Answer in units of m/s^2.
Answers
Answered by
bobpursley
The answer is dependent on if the tires are skidding or not, ie, since you did not mention the coefficent of rolling friction, I assume sliding (use coeff kinetic friction).
F=ma
a=F/m=mg*mu/m where mu is coeff Kinetic friction.
a=.1463*9.8m/s^2
F=ma
a=F/m=mg*mu/m where mu is coeff Kinetic friction.
a=.1463*9.8m/s^2
Answered by
Boyman
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