Asked by David
antiderivative of (x-2)/(x-1)
Answers
Answered by
Reiny
(x-2)/(x-1) = 1 - 1/(x-1)
so
integral[(x-2)/(x-1)] = integral[1 - 1/(x-1)
= x - ln(x-1) + C
so
integral[(x-2)/(x-1)] = integral[1 - 1/(x-1)
= x - ln(x-1) + C
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