Asked by Risper
In a geometric progression, the first term is a and the common ratio is r. The sum of the first two terms is 12 and the third term is 16.
determine the ratio ar^2/a+ar
determine the ratio ar^2/a+ar
Answers
Answered by
Bosnian
In G.P:
an = a ∙ r ⁿ ⁻ ¹
a1 = a
a2 = a r¹ = a r
a3 = a r²
The sum of the first two terms is 12 means:
a1 + a2 = 12
a + a r = 12
The third term is 16 means:
a3 = a ∙ r² = 16
a r² / ( a + a r ) = 16 / 12 = 4 ∙ 4 / 4 ∙ 3 = 4 / 3
an = a ∙ r ⁿ ⁻ ¹
a1 = a
a2 = a r¹ = a r
a3 = a r²
The sum of the first two terms is 12 means:
a1 + a2 = 12
a + a r = 12
The third term is 16 means:
a3 = a ∙ r² = 16
a r² / ( a + a r ) = 16 / 12 = 4 ∙ 4 / 4 ∙ 3 = 4 / 3
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.