Asked by Priscilla

The 3rd and 4th term of geometric progression are 4 and 8 respectively find:
The first term and common ratio,
The sum of the first 10 term,
The sum of infinity.

Answers

Answered by Priscilla
Anyone to help solve this pliz
Answered by mathhelper
Just apply the definitions:
3rd term = ar^2 = 4
4th term = ar^3 = 8
divide them
ar^3/(ar^2) = 8/4
r = 1/2
back in ar^2 = 4
a(1/4) = 4
a = 16

sum(10) = a(1 - r^10)/(1-r)
= 16( 1 - 1/1024)/(1 - 1/2)
= 16(1023/1024)(2/1) = 1023/32

sum(all terms) = a/(1-r)
= 16/(1/2) = 32
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