Asked by Anonymous
What volume of dry oxygen gass measured at s.t. p will produced from the decomposition of 40.5g of potassium trioxochlorate(v)?
(K=39,cl=35.5,o=16)
(K=39,cl=35.5,o=16)
Answers
Answered by
Kings
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Answered by
Kings
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Answered by
DrBob222
2KClO3 ==> 2KCl + 3O2
mols KClO3 = 40.5/122.5 = 0.3 estimated
0.3 mol KClO3 x (3 mols O2/2 mol KClO3) = 0.3 x 3/2 = 0.5 estimated
Then 0.5 mol O2 x 22.5 L/mol = approximate ?
You should go through and recalculate each since my numbers are just approximate. Post your work if you get stuck.
mols KClO3 = 40.5/122.5 = 0.3 estimated
0.3 mol KClO3 x (3 mols O2/2 mol KClO3) = 0.3 x 3/2 = 0.5 estimated
Then 0.5 mol O2 x 22.5 L/mol = approximate ?
You should go through and recalculate each since my numbers are just approximate. Post your work if you get stuck.
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