Asked by sweety

how much volume of oxygen at stp in litres is required to burn 4g of methane gas completely
Answered by DrBob222
CH4 + 2O2 ==> CO2 + 2H2O

mols CH4 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols CH4 to mols O2.
Now convert mols O2 to L O2 by mols O2 x 22.4 L/mol = L O2.
Answered by Theo
64.1
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