Question
What volume of oxygen gas is needed for the complete combustion of 4.00 L of ethane gas, C2H6? Assume that the temperature and pressure of the reactants are the same.
Answers
2C2H6 + 7O2 ==> 4CO2 + 6H2O
When gases are involved one can take a shortcut and use liters and mols interchangeably.
So 4.00 L C2H6 x (7 mols O2/2 mols C2H6) = 4.00 x 7/2 = ? L O2
When gases are involved one can take a shortcut and use liters and mols interchangeably.
So 4.00 L C2H6 x (7 mols O2/2 mols C2H6) = 4.00 x 7/2 = ? L O2
Is not there in my options
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